If the FFD increases from 1.0 m to 1.5 m, by what factor should the mAs be increased?

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Multiple Choice

If the FFD increases from 1.0 m to 1.5 m, by what factor should the mAs be increased?

Explanation:
When you move the focal film distance farther away, the X-ray beam spreads over a larger area, so the image receptor receives less exposure unless you compensate with higher mA·s. The exposure at the receptor is proportional to mAs divided by the square of the distance, so to keep the same receptor exposure as distance increases, you multiply mAs by the square of the distance ratio. Here, the distance goes from 1.0 m to 1.5 m. The ratio is 1.5, and squaring it gives 2.25. So you should increase mAs by a factor of 2.25. If the original mAs was X, the new mAs should be 2.25X.

When you move the focal film distance farther away, the X-ray beam spreads over a larger area, so the image receptor receives less exposure unless you compensate with higher mA·s. The exposure at the receptor is proportional to mAs divided by the square of the distance, so to keep the same receptor exposure as distance increases, you multiply mAs by the square of the distance ratio.

Here, the distance goes from 1.0 m to 1.5 m. The ratio is 1.5, and squaring it gives 2.25. So you should increase mAs by a factor of 2.25. If the original mAs was X, the new mAs should be 2.25X.

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