What happens to beam intensity when the FFD doubles?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $25.99Unlock all

Prepare for the VetSkill Level 3 Diploma VN02 – Diagnostic Principles Test. Engage with multiple-choice questions, hints, and explanations. Achieve your certification!

Multiple Choice

What happens to beam intensity when the FFD doubles?

Explanation:
Beam intensity follows the inverse square relationship with distance from the X-ray source. If the focal-film distance doubles, the intensity at the film becomes 1/2 squared, which is 1/4 of the original. So the beam intensity reduces to one quarter. The other options describe increases or only halves/doubles, which don’t fit this distance‑squared relationship (assuming no extra attenuation).

Beam intensity follows the inverse square relationship with distance from the X-ray source. If the focal-film distance doubles, the intensity at the film becomes 1/2 squared, which is 1/4 of the original. So the beam intensity reduces to one quarter. The other options describe increases or only halves/doubles, which don’t fit this distance‑squared relationship (assuming no extra attenuation).

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy